Hi,

I'm trying to solve the integral e^2xsin3x dx. I think I need to use the forumula int. usinudu=sinu-ucosu+c. Is that correct?

Would u be e^2x

du=e^2x(2)?????

So...int. usinudu=sinu-ucosu+c

=e^2xsine^2x=sine^2x-e^2xcose^2x+c

I don't think this is correct. Could someone please give me a hint?

Thank you