Now, finish it.
Hi,
I'm trying to solve the integral e^2xsin3x dx. I think I need to use the forumula int. usinudu=sinu-ucosu+c. Is that correct?
Would u be e^2x
du=e^2x(2)?????
So...int. usinudu=sinu-ucosu+c
=e^2xsine^2x=sine^2x-e^2xcose^2x+c
I don't think this is correct. Could someone please give me a hint?
Thank you