Find the differential dy of the given function y= (1/3) cos((6pi times x-1))/((2)) Can anyone help me with this problem?
Last edited by homeylova223; Aug 4th 2011 at 03:28 PM.
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There's no variable in the given function, so that means ...
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Last edited by homeylova223; Aug 4th 2011 at 03:10 PM.
That means you're taking the differential of a constant number, and what's the differential of a constant number? (in general: )
Actually I have to admit I made a typo y= (1/3) cos((6pi x-1))/((2)) is how it is correctly written I am sorry...
Do you know the chain rule? But write: But it's still not clear, you have to be more clear with: or ?
No in my textbook the problem is written ((1/3)) cos ((6pi times x-1))/((2)) The cos is outside the parenthesis It can be tough being clear sometimes.
Either way you'll have to use the chain rule for this one.
Originally Posted by homeylova223 No in my textbook the problem is written ((1/3)) cos ((6pi times x-1))/((2)) The cos is outside the parenthesis It can be tough being clear sometimes. is this it? you really need to learn Latex ...
Modified
Yes skeeter is correct. I have to apply the chain rule. Can anyone show me the first step?
If you want to use the chain rule here: . Can you go further? You don't have to use the quotienrule, just put outside, because it's a constant.
Alright following Siron adivce -sin((6pi times x-1))/((2)) times cos(6pi)(-1/2) would this be correct?
That's not correct, it has to be: Can you now finish the differential of the given function.
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