With the information given compare delta y and dy.

1. y=(x)^3 x=1 delta x= 0.1

dy= f'(x)(dx)

dy= 3(1)(0.1)

dy=.3

delta y= f(x+delta x)- f(x) I am having trouble finding delta y

delta y= (1+.1)-(1) ? Is this what I would do

My second question is similar

2.y= x^4+1 x=-1 and delta x=.01

dy=(-4)(-1)(.01)

dy=.04

But I am having trouble finding delta y