f is continues on [a,b]
A={x in [a,b]|f(x)=f(a)}
prove that f(x) has a maximum
f(supA)=f(a)
??
first of all there are two kinds of maximums here
1st a supremum which is inside [a,b] is called maximum
and maximum of the function values
correct??
f is continues on [a,b]
A={x in [a,b]|f(x)=f(a)}
prove that f(x) has a maximum
f(supA)=f(a)
??
first of all there are two kinds of maximums here
1st a supremum which is inside [a,b] is called maximum
and maximum of the function values
correct??
Because $\displaystyle \left( {\forall x \in A} \right)\left[ {x \leqslant b} \right]$, you know that $\displaystyle \beta=\sup\{A\}$ exists and $\displaystyle \beta\in[a,b]$.
If it is true $\displaystyle \beta\in A$ you are done.
Else If you assume $\displaystyle \beta\notin A$ that leads to a contradiction to the continuity of $\displaystyle f$.
BTW: This not the Extreme value theorem.