the Absoulute max and min f(x)=x^4 -2x^2 +3 on [-2,3] is at x=?
I do not know how to do this.
here are my thoughts.
1) take derivative of f(x) and set equal to 0
f'(x)= 4x^3 -4x = 0
4x(4x^2-1) =0
x=0
x= +1/2
x= -1/2
f(0) = 3
f(1/2) = 2.54 ???
I am confused![]()