Find the zeroes of the function using Newtons method.
I find that when x=11.803 y=0
Then I do Newtons method ((xn))-((f(x)n))/((f'(x)n))
I find that when x=11.803 y=11.803
So Did I do this correctly?
That's essentially how you tell when you have arrived at a solution- when the iteration starts giving you the same number again and again.
I am not sure what you did! You say found that "when x= 11.803, f(x)= 0". How did you find that value of x? And once you have found it why then put that value into the Newton's method formula?So Did I do this correctly?
I ran a quick Newton's method starting with
and got , , , , , , ,
Since we are now getting the same result, we can say that one solution, to three decimal places, is 11.803.