# Math Help - What is the limit of this series?

1. ## What is the limit of this series?

where a, b and e are constants. g and n are obvious from the sum. How can I find the limit of this series as n approaches infinity? I already tried several approaches, but it's always problematic as the "g" is under the square root sign.

2. ## Re: What is the limit of this series?

Originally Posted by Supernova008

where a, b and e are constants. g and n are obvious from the sum. How can I find the limit of this series as n approaches infinity? I already tried several approaches, but it's always problematic as the "g" is under the square root sign.
First lump your constants, put $A=|ea|$, and $c=|b/ea|$ then you have:

$A \sum_{k=1}^n \frac{1}{n}\sqrt{(k/n)^2+c^2}$

The sum can be interpreted as a Riemann sum for an integral from 0 to 1 of a continuous function so the limit is:

$A \int_0^1 \sqrt{x^2+c^2}\; dx$

CB

3. ## Re: What is the limit of this series?

Originally Posted by CaptainBlack
First lump your constants, put $A=|ea|$, and $c=|b/ea|$ then you have:

$A \sum_{k=1}^n \frac{1}{n}\sqrt{(k/n)^2+c^2}$

The sum can be interpreted as a Riemann sum for an integral from 0 to 1 of a continuous function so the limit is:

$A \int_0^1 \sqrt{x^2+c^2}\; dx$

CB
I am not a university student yet, so pardon my lack of such advanced mathematical knowledge. I am currently researching this riemann sum, but could you tell me why this is so?

EDIT: the first term of the sum is (1/n)*sqrt(1/n^2 + m^2)
however, the first term of the riemann sum is 1/n*sqrt(n^2+m^2), right? isn't that an inconsistency?

4. ## Re: What is the limit of this series?

Originally Posted by Supernova008
I am not a university student yet, so pardon my lack of such advanced mathematical knowledge. I am currently researching this riemann sum, but could you tell me why this is so?

EDIT: the first term of the sum is (1/n)*sqrt(1/n^2 + m^2)
however, the first term of the riemann sum is 1/n*sqrt(n^2+m^2) , right? isn't that an inconsistency?
What does the red text above refer to?

The partitioning points are $1/n,\ 2/n,\ 3/n,\ ...\ ,\ n/n$ and $h=1/n$.

(not advanced mathematical knowlege, this was taught in what would now be years 11 or 12 when I was in secondary education)

CB

5. ## Re: What is the limit of this series?

Originally Posted by CaptainBlack
What does the red text above refer to?

The partitioning points are $1/n,\ 2/n,\ 3/n,\ ...\ ,\ n/n$ and $h=1/n$.

(not advanced mathematical knowlege, this was taught in what would now be years 11 or 12 when I was in secondary education)

CB
Yeah sorry, I got it already, thank you very much!