position of particle is given s=t^3 -12t^2 +45t+10 Do subsitibe t=0 and t=3 into s=t^3 -12t^2 +45t+10 or into its derivative? s=t^3 -12t^2 +45t+10 is s' =3t^2 -24t +45 = V(velocity)?
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Originally Posted by NeoSonata position of particle is given s=t^3 -12t^2 +45t+10 Do subsitibe t=0 and t=3 into s=t^3 -12t^2 +45t+10 or into its derivative? s=t^3 -12t^2 +45t+10 is s' =3t^2 -24t +45 = V(velocity)? s(3) - s(0), divided by (3 - 0), represents the average velocity.
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