I am having more trouble with this then I probably should be, I just can't seem to figure it out. Its $\displaystyle e^{-2x}-3e^{-x}=-2$ Thanks as always. Ryan.
Follow Math Help Forum on Facebook and Google+
Originally Posted by rushton I am having more trouble with this then I probably should be, I just can't seem to figure it out. Its $\displaystyle e^{-2x}-3e^{-x}=-2$ Thanks as always. Ryan. Substitute: $\displaystyle e^{-x}=t$ so...
Of course, now you say that it is smacking me in the face. I tried other substitutions but not that one for some silly reason. Thanks a lot!