I'm looking to integrate:
1/(2x+5)
Wolframalpha.com displays the answer as:
1/2 log(2x+5)
My problem is with the (1/2) in the answer. Wolfram claims that you substitute u=2x+5 and du=2dx, but then goes on to take the 1/2 out before substituting then integrating...
Could someone take me step by step through this?