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Math Help - ∫▒(2-3v)/(2v^2-3v) □(24&dv

  1. #1
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    ∫▒(2-3v)/(2v^2-3v) □(24&dv


    ∫(2-3v)/(2v^2-3v)dv and
    ∫(1/1+cosu)du

    pls having problem integrating the equation above, help!!!
    Last edited by lawochekel; July 29th 2011 at 01:12 AM. Reason: correction
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  2. #2
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    Re: ∫▒(2-3v)/(2v^2-3v) □(24&dv

    \frac{2 - 3v}{2v^2 - 3v}

    = \frac{2 - 3v}{v(2v - 3)}\ =\ \frac{A}{v}\ +\ \frac{B}{2v - 3}

    (find A and B...)

    \frac{1}{1 + \cos u} = \frac{1 - \cos u}{(1 + \cos u)(1 - \cos u)}

    (where you have a difference of two squares on the bottom (followed by trig/pythag), and the top splits in two...)
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