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Math Help - where the function is concave down and concave up

  1. #1
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    where the function is concave down and concave up

    f(x) = x^2 / (x^2 - 16)

    f'(x) = -32x/(x^2-16)^2

    x= -4,0,4


    f''(x) = (96x^2 +512) / (x^2 -16)^3

    how do i do this?
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  2. #2
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    Re: where the function is concave down and concave up

    Quote Originally Posted by NeoSonata View Post

    f''(x) = (96x^2 +512) / (x^2 -16)^3

    how do i do this?
    sub the values for x you found for the stationary points.

    If \displaystyle f''(x_0) > 0 \implies min

    and \displaystyle f''(x_0) < 0 \implies max
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