1. ## Vector Calculus

Question

Find the surface area of that portion of the sphere x^2 + y^2 + z^2 = a^2 that is above xy-plane and within the cylinder x^2 + y^2 = b^2 , 0 < b < a

Solution.. i try to find fx and fy..

how am i going to proceed?

2. ## Re: Vector Calculus

You'll obtain $A=a\iint_{D}\dfrac{dxdy}{\sqrt{a^2-x^2-y^2}}$ with $D\equiv x^2+y^2\leq b^2$ now, use polar coordinates.