# Vector Calculus

• July 25th 2011, 05:15 AM
nameck
Vector Calculus
Question

Find the surface area of that portion of the sphere x^2 + y^2 + z^2 = a^2 that is above xy-plane and within the cylinder x^2 + y^2 = b^2 , 0 < b < a

Solution.. i try to find fx and fy..
Attachment 21887

how am i going to proceed? (Bow)
http://www.mathhelpforum.com/math-he...isc/pencil.png
• July 25th 2011, 09:09 AM
FernandoRevilla
Re: Vector Calculus
You'll obtain $A=a\iint_{D}\dfrac{dxdy}{\sqrt{a^2-x^2-y^2}}$ with $D\equiv x^2+y^2\leq b^2$ now, use polar coordinates.