Let
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Your substitution is ok. Now calculate: The integral becomes: Now you can use the t-formulas or the substitution, let .
Last edited by Siron; Jul 24th 2011 at 02:35 AM.
it will be easier to use hyperbolic substitution let x = (3/2) sinh (theta) gives dx = (3/2)cosh (theta) d(theta)
Last edited by waqarhaider; Jul 24th 2011 at 04:31 AM. Reason: may be I use Latex wrong
Originally Posted by Punch Let you forgot to square 3/2 and substitute for dx since ... back substitute ...
Hello, Punch! . . Substitute: . Back-substitute: . We have: . ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ This can be simplified even further . . . . . . . . .
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