Can anyone help me find the derivative of this function f(x)=((x^3-3x^2+4))/((x^2)) This is what I did ((3x^2-6x+0))/((2x)) But How would I proceed
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Originally Posted by homeylova223 Can anyone help me find the derivative of this function f(x)=((x^3-3x^2+4))/((x^2)) But How would I proceed $\displaystyle \text{If }f(x) = \frac{{g(x)}}{{h(x)}}\text{ then }f'(x) = \frac{{g'(x)h(x) - h'(x)g(x)}}{{\left[ {h(x)} \right]^2 }}$
Unfortunately all I have learned thus far is the power rule. But I will try to work it out.
Originally Posted by homeylova223 Can anyone help me find the derivative of this function f(x)=((x^3-3x^2+4))/((x^2)) This is what I did ((3x^2-6x+0))/((2x)) But How would I proceed You are probably expected to use basic algebra and index laws to re-arrange into the form $\displaystyle f(x) = \frac{x^3}{x^2} - \frac{3x^2}{x^2} + \frac{4}{x^2} = x - 3 + 4 x^{-2}$.
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