this is your integral ?
Hey There,
I am doing a question and I can solve it the antiderivative way, but I can't seem to come up with the substitution method.
3 + x^3/2 dx
__ _____ divide by
x^3 3
So I put the integral sign 3x^-3 - 3x^3/2 dx
now do I take out a 3 and have 3(x^-3-3x^3/2) dx or NO??
I can't figure out the U and du.
Any help would be great, thanks.