The tangent to the curve of y=ax^2 + bx +c at the point where x=2 is parallel to the line y=4x. There is a stationary point at (1, -3). Find the value of a, b and c.
I was really unsure of how to work out this question, so first I differentiated y.
The point (1, -3) is on the curve and therefore:
But I don't know how to find another equation, and I honestly don't even know if what I've done so far is on the right track.