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Math Help - Help with a tricky implicit equation...

  1. #1
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    Help with a tricky implicit equation...

    Hello,

    I'm trying to solve this implicit equation for Ecarb:

    (A*((D*ECARB)+(E*log((F+(G*ECARB))/H)))) = 1

    I believe this is possible provided all other values are known.


    Can anyone help with this?

    Charles
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  2. #2
    MHF Contributor Siron's Avatar
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    Re: Help with a tricky implicit equation...

    Are A,D, ... just constants?
    Use:
    log(a.b)=log(a)+log(b)
    log(a/b)=log(a)-log(b)

    I haven't checked if it's possible, try to do it with these rules, but maybe it's not possible.

    EDIT:
    Can you say more about A,D,...?
    Last edited by Siron; July 10th 2011 at 01:14 PM.
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  3. #3
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    Re: Help with a tricky implicit equation...

    Yes, A, D etc are all constants. Only ECARB is unknown. Thankyou
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  4. #4
    MHF Contributor Siron's Avatar
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    Re: Help with a tricky implicit equation...

    The second term:
    log((F+G.Ecarb)/H)=log(F+G.Ecarb)-log(H)
    The problem is here:
    log(F+G.Ecarb)
    You can't split up Ecarb and the constants.
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  5. #5
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    Re: Help with a tricky implicit equation...

    Hi, thanks for the reply. That's what I noticed too. Apparently it's the Netwon-Raphson method to solve it.
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