Hello,

I'm trying to solve this implicit equation for Ecarb:

(A*((D*ECARB)+(E*log((F+(G*ECARB))/H)))) = 1

I believe this is possible provided all other values are known.

Can anyone help with this?

Charles

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- Jul 10th 2011, 11:48 AMccdean100Help with a tricky implicit equation...
Hello,

I'm trying to solve this implicit equation for Ecarb:

(A*((D*ECARB)+(E*log((F+(G*ECARB))/H)))) = 1

I believe this is possible provided all other values are known.

Can anyone help with this?

Charles - Jul 10th 2011, 12:01 PMSironRe: Help with a tricky implicit equation...
Are A,D, ... just constants?

Use:

log(a.b)=log(a)+log(b)

log(a/b)=log(a)-log(b)

I haven't checked if it's possible, try to do it with these rules, but maybe it's not possible.

EDIT:

Can you say more about A,D,...? - Jul 10th 2011, 12:16 PMccdean100Re: Help with a tricky implicit equation...
Yes, A, D etc are all constants. Only ECARB is unknown. Thankyou

- Jul 10th 2011, 12:22 PMSironRe: Help with a tricky implicit equation...
The second term:

log((F+G.Ecarb)/H)=log(F+G.Ecarb)-log(H)

The problem is here:

log(F+G.Ecarb)

You can't split up Ecarb and the constants. - Jul 10th 2011, 12:38 PMccdean100Re: Help with a tricky implicit equation...
Hi, thanks for the reply. That's what I noticed too. Apparently it's the Netwon-Raphson method to solve it.