Hello,

Covering the topic of Indefinite Integral:

I am doing a question, which my book does not give the answer and hoping someone can look at it and tell me if I did this right.

Integre/sign then ( x^2 + 4x + 4 ) ^ 1/3 dx

So I worked out 1/3 to the numbers in the brackets.

So I have Int Sign ( x^7/3 + 4 x^4/3 + 4^1/3)

then:

int sign x^7/3 dx + 4 intsign x^4/3 dx + 4^1/3 intsign dx

So my answer is

3/10 x^10/2 + 12/7 x^7/3 + 4^1/3 x + C.

is this correct? or not, thanks.

Joanne