Hi everyone,

Can someone give me a hint on how to do this problem, please? I've tried it several different ways, but it doesn't seem to be working.

Find the integral x to the 5thcos(x cubed)dx

u=x to the 3rd

dv=x to the 5th

du=3x2

v=x6/6

(x to the 3rd)(x to the 5th)=(x to the 3rd)(x to the 6th)-int.(x to the 6th/6)3x sq.

but this integral looks worse

Any suggestions?

Thank you