Hi everyone,
Can someone give me a hint on how to do this problem, please? I've tried it several different ways, but it doesn't seem to be working.
Find the integral x to the 5thcos(x cubed)dx
u=x to the 3rd
dv=x to the 5th
du=3x2
v=x6/6
(x to the 3rd)(x to the 5th)=(x to the 3rd)(x to the 6th)-int.(x to the 6th/6)3x sq.
but this integral looks worse
Any suggestions?
Thank you