The integral of [ 1 / t^3 * sqrt(t^2 - 1) ] from sqrt(2) to 2.
Can someone help me in getting the integral..
I tried u substitution but got stuck..
u = sqrt(t^2-1)
du/dt = (1/2)(sqrt(t^2-1)^-(1/2)
du = " " * dt
dV = t^3
v = t^4/4
Is this the right way? I get stuck after I rewrite it..
is there an easier way, thank you