The integral of [ 1 / t^3 * sqrt(t^2 - 1) ] from sqrt(2) to 2.

Can someone help me in getting the integral..

I tried u substitution but got stuck..

u = sqrt(t^2-1)

du/dt = (1/2)(sqrt(t^2-1)^-(1/2)

du = " " * dt

dV = t^3

v = t^4/4

Is this the right way? I get stuck after I rewrite it..

is there an easier way, thank you