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Math Help - Triple integral to find volume

  1. #1
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    Triple integral to find volume

    Calculate the volume bounded by the surface 9 + x + y = z , z = 1 , x^2 +y^2 = 4?



    i try to convert the range into cylindrical coordinate first..

    i know the range for phi and r..
    i just dont know the range of z..

    where i try z is from 0 to 9 + r (dont know whether it is correct or not..)
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  2. #2
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    Re: Triple integral to find volume

    Quote Originally Posted by nameck View Post
    Calculate the volume bounded by the surface 9 + x + y = z , z = 1 , x^2 +y^2 = 4?



    i try to convert the range into cylindrical coordinate first..

    i know the range for phi and r..
    i just dont know the range of z..

    where i try z is from 0 to 9 + r (dont know whether it is correct or not..)
    This surface is formed from the cylinder x^2+y^2=4 by slicing it off at the bottom by the plane z=1, and at the top by the plane z= 9+x+y. So the lower limit for z is 1 (not 0), and the upper limit is 9+x+y, which you have to write as 9+r(\cos\theta+\sin\theta).
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