I am half way stuck with this integral, any help would be appreciated.
Integral (p^5)ln(p) dp
u = ln p, du = 1/p
dv = p^5, v = p^6/6
Integral (p^5)ln(p) dp = p^6/6 ln(p) - Integral p^6/6p dp
Im stuck at the integral, substitution doesn't seem to work if I let w = p^6, dw = 6p^5..