Integral of [sqrt(t)*ln t]dt from 1 to 4. I tried to do substitution but I think I am doing it wrong u = ln t du/dt = 1/t tdu = dt the square root in the original problem is confusing me. can someone help? thanks
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Did you try, integration by parts?
Originally Posted by Krizalid Did you try, integration by parts? oh wow I forgot about that. thank you lol, i got the answer
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