Why do you believe you should be able to do it?
Have you noticed the symmetry about x = 1? And the limited Domain, 0 <= x <= 2?
I am trying to integrate this expression and I can't seem to be able to do so. I would greatly appreciate it if you can help me. The expression is: 1/(1 + sqr(2x - x^2)).
I tried multiplying the denominator with 1- sqr(2x - x^2) but to no avail. I then tried to rewrite the numerator as 1 - x + x, still stuck. I also tried to rewrite the denominator as (u - 2)/2, but I failed to find a solution. anyone any hint, please?
I believe I should be able to evaluate the integral because it was on a test in the past at the school I go.
that is the expression I arrived at, but did not have the idea of reforming it into a trig expression. I guess I will write x - 1 = sin (or perhaps cos), and see what I get.
Thank you all for your reply.
You must answer this question: Are the first and last expressions equivalent? . If they are, then you're done. If they are not, what are you going to do about the transformation?
TKHunny, impress my teacher? I'd rather not before I get into wining and complaining about all the wrong at school, I'll just ask you or skeeter whether I integrated correctly 'the second' expression that skeeter derived. otherwise, I understand you perfectly well, TKHunny. You do have a point.
The substitutions I did are as follows: