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**circuscircus** $\displaystyle = \int [sec(\frac{x}{2}) + tan(\frac{3x+1}{5} )+ tan(7x)] dx$

$\displaystyle = \int sec(\frac{x}{2}) + \int tan(\frac{3x+1}{5} ) + \int tan(7x) dx$

$\displaystyle = 2ln|sec\frac{x}{2} + tan\frac{x}{2}| + \int tan(\frac{3x+1}{5} )+ \int tan(7x) dx$

$\displaystyle = 2ln|sec\frac{x}{2} + tan\frac{x}{2}| + (\frac{5}{3})(-ln|cos \frac {3}{5} | ) + (\frac{1}{7})(-ln|cos 7|)$

$\displaystyle = 2ln|sec\frac{x}{2} + tan\frac{x}{2}| -\frac{5}{3}ln|cos \frac {3}{5} | -\frac{1}{7}ln|cos 7|$

I don't have an answer to check but could someone give a thumbs up if they don't see anything wrong with it?