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Math Help - what is the mistake here

  1. #16
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    Re: what is the mistake here

    You are working with the sphere [tex]x^2+ y^2+ z^2= 2z[/itex], a sphere of radius 1, centered at (0, 0, 1). In spherical coordinates, x= \rho cos(\theta)sin(\phi), y= \rho sin(\theta)sin(\phi), z= \rho cos(\theta). Since the radius of the sphere is 1, \rho= 1 and we have x^2+ y^2+ z^2= 1 and 2z= 2cos(\phi).
    Last edited by Ackbeet; July 2nd 2011 at 07:23 PM.
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  2. #17
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    Re: what is the mistake here

    Quote Originally Posted by transgalactic View Post
    z=\rho cos \theta
    what to do now?
    Do you mean \theta or \phi ?
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