Can you help me with this problem, please?
Find the integral
int. x^2-x+6/x^3+3xdx=int. x^2-x+6/x(x^2+3)dx
I don't know what to do from here. I was going to plug in 3a with 3(1-B), but that isn't going to help since I still have an x. Can someone give me a hint, please?