Standard Exponent Rule, isn't it?
For suitable values of 'a', we have
a = -1 is a suitable value.
The next step i'm confused about:
. not quite right
I think I am overlooking something here . . .
How does the come to be squared? Underneath the 6000?
Are you sure you know your differentiation rules?
You can use the Quotient Rule,
. . which ends with "over the denominator squared".
Or use an easier way . . .
We have: .
Chain Rule: .
. . . . . . . . . .
When your numerator is a constant, as here, it is perhaps easier to think of the problem as having a negative exponent:
Now, that the derivative is
So you can think of the denominator being being squared as a result of either the quotient rule or simply the power rule: with n= -1 so that n-1= -1-1= -2.
Note that to finish you will need the fact that the derivative of is .