# Thread: Vector Calculus (area II)

1. ## Vector Calculus (area II)

Calculate the area of the cone $\ z = \sqrt {x^2 + y^2}$, that is inside cylinder $x^2 + y^2 \leq 2x$, outside the cylinder $x^2 + y^2 \leq 1$ and above the plane xy.

A.: $\frac {\sqrt{2} (2\pi + 3 \sqrt{3})} {6}$

2. ## Re: Vector Calculus (area II)

Are you sure it's not asking you to calculate the VOLUME, not the area?

3. ## Re: Vector Calculus (area II)

Yes, I'm sure. The formula is: $A = \iint \limits_S \left ||{{\vec{r_u}.\vec{r_v}}} \right || dA$

4. ## Re: Vector Calculus (area II)

Yes, I'm sure. The formula is: $A = \iint \limits_S \left ||{{\vec{r_u}.\vec{r_v}}} \right || dA$.

But I can't figure out the limits of integration.

--> I'm sorry for the repeated post (how can I delete the first one?)