# Vector Calculus (area II)

• June 21st 2011, 10:02 AM
PedroMinsk
Vector Calculus (area II)
Calculate the area of the cone $\ z = \sqrt {x^2 + y^2}$, that is inside cylinder $x^2 + y^2 \leq 2x$, outside the cylinder $x^2 + y^2 \leq 1$ and above the plane xy.

A.: $\frac {\sqrt{2} (2\pi + 3 \sqrt{3})} {6}$
• June 21st 2011, 10:16 AM
Prove It
Re: Vector Calculus (area II)
Are you sure it's not asking you to calculate the VOLUME, not the area?
• June 21st 2011, 10:38 AM
PedroMinsk
Re: Vector Calculus (area II)
Yes, I'm sure. The formula is: $A = \iint \limits_S \left ||{{\vec{r_u}.\vec{r_v}}} \right || dA$
• June 21st 2011, 10:39 AM
PedroMinsk
Re: Vector Calculus (area II)
Yes, I'm sure. The formula is: $A = \iint \limits_S \left ||{{\vec{r_u}.\vec{r_v}}} \right || dA$.

But I can't figure out the limits of integration.

--> I'm sorry for the repeated post (how can I delete the first one?)