Hey everyone. I have to revolve the surface bounded by $\displaystyle y=x\sqrt{x+1}$ and y = 0 around the y-axis and find the volume underneath it. I just have to set up the integral from [a,b]. The problem is, I don't know how to take the inverse of that function. From there I can just do

$\displaystyle \pi\int_a^b[ f^{-1}(x)]^2dx$

What should i do?

Thanks in advance!