I need to find the Integral with respect to x of (e^(-.02x))/(8-e^(-.02x))
I use u=8-e^(-.02x)
and find that dx= du/.02e^(-.02x) or dx=50du/e^(-.02x)
when i substitute that back into the integral, the integral reduces to:
integral of (50/u)du which equals 50ln(abs(u))+ c
after substituting back in for u I finished with
Where did I mess up?