is my u=4+3t^2?
Last edited by mr fantastic; June 18th 2011 at 09:24 PM. Reason: Fixed the latex.
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that won't work because, then . Since there is no t on the upper side of the fraction (sorry I can't remember the name that is called) it will be a dead end. try using the identity,
Originally Posted by purplec16 [tex]int_{-2^2}{\frac{3dt}{4+3t^2}}[\tex] is my u=4+3t^2? Why not try
Originally Posted by BAdhi that won't work because, then . Since there is no t on the upper side of the fraction (sorry I can't remember the name that is called) it will be a dead end. try using the identity, Yes, but using t's instead of x's, of course ..... @OP: And since the integrand is even, you can integrate from 0 to 2 and then double the resulting answer.
Originally Posted by BAdhi that won't work because, then . Since there is no t on the upper side of the fraction (sorry I can't remember the name that is called) it will be a dead end. In English, the "numerator" (and the lower side is the "denominator"). try using the identity,
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