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Math Help - difficult integral

  1. #16
    Math Engineering Student
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    \tan\frac\pi6=\frac1{\sqrt3} and \tan\frac\pi4=1

    What can you get from there?
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  2. #17
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    Would I take the inverse of both? I don't remeber what to do with this. I'm not sure if this right or not.

    and
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  3. #18
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    Quote Originally Posted by Krizalid View Post
    \tan\frac\pi6=\frac1{\sqrt3} and \tan\frac\pi4=1
    This means that \arctan\frac1{\sqrt3}=\frac\pi6 & \arctan1=\frac\pi4

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  4. #19
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    Also, I can't simplify 1/2ln4-ln1 right?

    Thank you
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  5. #20
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by chocolatelover View Post
    Also, I can't simplify 1/2ln4-ln1 right?

    Thank you
    \frac {1}{2} \ln 4 = \ln 4^{1/2} = \ln 2

    \ln 1 = 0 ............by the way, where did you get ln 1 from? there is no ln 1
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