Math Help - difficult integral

1. $\tan\frac\pi6=\frac1{\sqrt3}$ and $\tan\frac\pi4=1$

What can you get from there?

2. Would I take the inverse of both? I don't remeber what to do with this. I'm not sure if this right or not.

and

3. Originally Posted by Krizalid
$\tan\frac\pi6=\frac1{\sqrt3}$ and $\tan\frac\pi4=1$
This means that $\arctan\frac1{\sqrt3}=\frac\pi6$ & $\arctan1=\frac\pi4$

4. Also, I can't simplify 1/2ln4-ln1 right?

Thank you

5. Originally Posted by chocolatelover
Also, I can't simplify 1/2ln4-ln1 right?

Thank you
$\frac {1}{2} \ln 4 = \ln 4^{1/2} = \ln 2$

$\ln 1 = 0$ ............by the way, where did you get ln 1 from? there is no ln 1

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