$\displaystyle \tan\frac\pi6=\frac1{\sqrt3}$ and $\displaystyle \tan\frac\pi4=1$ What can you get from there?
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Would I take the inverse of both? I don't remeber what to do with this. I'm not sure if this right or not. and
Originally Posted by Krizalid $\displaystyle \tan\frac\pi6=\frac1{\sqrt3}$ and $\displaystyle \tan\frac\pi4=1$ This means that $\displaystyle \arctan\frac1{\sqrt3}=\frac\pi6$ & $\displaystyle \arctan1=\frac\pi4$
Also, I can't simplify 1/2ln4-ln1 right? Thank you
Originally Posted by chocolatelover Also, I can't simplify 1/2ln4-ln1 right? Thank you $\displaystyle \frac {1}{2} \ln 4 = \ln 4^{1/2} = \ln 2$ $\displaystyle \ln 1 = 0$ ............by the way, where did you get ln 1 from? there is no ln 1
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