hey there..
The question is..
lambda = x (i dont know how to type the symbol..)
Let A be n x n square matrix. Suppose that
det(xI-A) = c(x) = x^3- 3x^2 + x + 6..
I know the answer is -6 by substitute lambda@x with 0..
However.. i just want to know.. why should i substitute it with 0..?
Thanks in advance..
yup2... so.. -(det A) = 6.. so.. det A = -6 right?
ok then.. why it is 0?
Got one more question..
if i've got 4 x 4 matrix,
the sign will be positive?
(-1)^4 det(A) correct?
Thanks HallsofIvy.. U are always answering my question perfectly..