I am not sure with that. The rational function will be very ugly ...
Not so bad, though, from a Calculus standpoint. Notice that the denominator is a biquadratic: . Use a substitution u = t^2 and the form will be much more recognizable.
The bottom factorises to , so the next step is partial fractions.
How did you obtain this factorisation, if you don't mind me asking? I'm not seeing it; neither can I find a clever/painless way of solving the integral!
How did you obtain this factorisation, if you don't mind me asking? I'm not seeing it; neither can I find a clever/painless way of solving the integral!