ok I know how integrals work and I have been using integrals to find area under the curves, I know integration by U sub and also by parts. but for some reason maybe it just slipped my mind but how do I integrate:
integral tan (3x-1),x
I started off by doing a u sub as u = (3x-1) and where i got 1/3du = dx,
so my new equation became 1/3 int tan u du then i realized i don't know the integral of tan u. Can someone show me the steps using natural logs to the answer. I searched it on wolframaplpha but it gave me a log answer. Any help is appreciated.