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**mjfuentes85** ok I know how integrals work and I have been using integrals to find area under the curves, I know integration by U sub and also by parts. but for some reason maybe it just slipped my mind but how do I integrate:

integral tan (3x-1),x

I started off by doing a u sub as u = (3x-1) and where i got 1/3du = dx,

so my new equation became 1/3 int tan u du then i realized i don't know the integral of tan u. Can someone show me the steps using natural logs to the answer. I searched it on wolframaplpha but it gave me a log answer. Any help is appreciated.

-Marcus