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Math Help - Rate of change of power

  1. #1
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    Rate of change of power

    I used an image because I already had the format done:

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  2. #2
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    Are you familiar with the differential calculus? You need to look up the "Quotient Rule".

    Also, the notation is lacking. "130/" is no good.
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  3. #3
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    I've learned the quotient rule.
    I don't understand what you mean by that :S


    I've tried solving the problem by using the quotient rule but I ended up with a very different answer than from the back.
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  4. #4
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    P = \frac{130R}{(R+0.8)^2}

    \frac{dP}{dR} = \frac{(R+0.8)^2 \cdot 130 - 130R \cdot 2(R+0.8)}{(R+0.8)^4}

    \frac{dP}{dR} = \frac{130(R+0.8)[(R+0.8)-2R]}{(R+0.8)^4}

    \frac{dP}{dR} = \frac{130(0.8-R)}{(R+0.8)^3}
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  5. #5
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    Thanks - I did it again and it worked. I derived in wrong in the first place.
    Thanks.
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