the range of function

f(x)=tan(2sqrt(x-4)+sqrt(6-x)) is

i know x is (-pi/2,pi/2)

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- Jun 10th 2011, 09:44 AMpratrange
the range of function

f(x)=tan(2sqrt(x-4)+sqrt(6-x)) is

i know x is (-pi/2,pi/2) - Jun 10th 2011, 10:03 AMe^(i*pi)
Do you see why the domain is $\displaystyle x - 4 \geq 0$ and $\displaystyle 6-x \geq 0$?

The range will be between these two points - Jun 10th 2011, 10:06 AMAckbeetQuote:

Originally Posted by**prat**

$\displaystyle f(x)=2\sqrt{x-4}+\sqrt{6-x}.$

You must first find the domain and range of this function. That's step 1. Step 2 is to use the range of this function as the domain of the tangent function, and see if there are any further restrictions. Can you see your way forward?