Is it possible to solve any of these equations?

$\displaystyle x = A[1-\cos (\omega t)]-\frac{Bt^{2}}{2}$

(Findt(x))

$\displaystyle A\cos (2\tau )-B(\cos \tau -\tau \sin \tau )=0$

(Find $\displaystyle \tau $)

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- Jun 8th 2011, 12:21 PMfysikbengtIs it possible to solve these equations?
Is it possible to solve any of these equations?

$\displaystyle x = A[1-\cos (\omega t)]-\frac{Bt^{2}}{2}$

(Find*t(x)*)

$\displaystyle A\cos (2\tau )-B(\cos \tau -\tau \sin \tau )=0$

(Find $\displaystyle \tau $) - Jun 8th 2011, 01:31 PMTKHunny
The Taylor Series expansion of cos(wt) may produce acceptable results.

Numerica methods, given specific values of A and B, certainly would produce acceptable results. - Jun 8th 2011, 02:43 PMfysikbengt
Yes, I don't have numerical values for A and B, but since $\displaystyle \omega t$ is between 0 and pi/2 I think the Taylor expansion is a good one.