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Math Help - Average value of integrals?

  1. #1
    Junior Member
    Joined
    Apr 2011
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    68

    Average value of integrals?

    I figured it out, sorry for the bother!

    hi guys can you please help me with this:

    Given f(x)=(x+1)^2
    Find the average value of f on [-1,1].


    is this it:

    u=x+1
    du=1dx

    \frac{1}{2} [\frac{u^3}{3}]^{2}_{0}

    \frac{1}{2}[\frac{(2)^3}{3} - \frac{(0)^3}{3}]

    \frac{1}{2}[\frac{8}{3}]

    4/3
    Last edited by RezMan; June 7th 2011 at 06:07 PM.
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