I know how to differentiate Sin x and Cos x using first principles.But how to do that to cosec x and sec x? Thanks
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$\displaystyle \sec(x+h) = \dfrac{1}{\cos(x+h)}$ So you'd have $\displaystyle f'(x) = \lim_{h \to 0} \dfrac{\dfrac{1}{\cos(x+h)} - \dfrac{1}{\cos(x)}}{h}$
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