find d/dx e^x ln x

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- Feb 6th 2006, 09:20 PMkdstalnakerHere's another one
find d/dx e^x ln x

- Feb 6th 2006, 11:12 PMCaptainBlackQuote:

Originally Posted by**kdstalnaker**

$\displaystyle \frac{d}{dx} \{ f(x)g(x) \} = \frac{df}{dx}g(x)+f(x)\frac{dg}{dx}$

So here we let $\displaystyle f(x)=e^x$ and $\displaystyle g(x)=\ln(x)$, and

from here I'm sure you can complete the answer.

RonL - Feb 7th 2006, 02:10 PMThePerfectHacker
$\displaystyle e^x\ln x+\frac{1}{x}e^x=e^x(\ln x+\frac{1}{x})$