Results 1 to 3 of 3

Thread: Here's another one

  1. February 6th 2006, 09:20 PM #1
    kdstalnaker
    kdstalnaker is offline
    Newbie
    Joined
    Apr 2005
    Posts
    23

    Here's another one

    find d/dx e^x ln x
    Follow Math Help Forum on Facebook and Google+
  2. February 6th 2006, 11:12 PM #2
    CaptainBlack
    CaptainBlack is offline
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    3
    Quote Originally Posted by kdstalnaker
    find d/dx e^x ln x
    Product rule:

    \frac{d}{dx} \{ f(x)g(x) \} = \frac{df}{dx}g(x)+f(x)\frac{dg}{dx}

    So here we let f(x)=e^x and g(x)=\ln(x), and
    from here I'm sure you can complete the answer.

    RonL
    Follow Math Help Forum on Facebook and Google+
  3. February 7th 2006, 02:10 PM #3
    ThePerfectHacker
    ThePerfectHacker is offline
    Global Moderator ThePerfectHacker's Avatar
    Joined
    Nov 2005
    From
    New York City
    Posts
    10,603
    e^x\ln x+\frac{1}{x}e^x=e^x(\ln x+\frac{1}{x})
    Follow Math Help Forum on Facebook and Google+
« Am I Right? | Countinous after derivative »

/mathhelpforum @mathhelpforum