Find the order of the pole f(z) = 1/(2cosz-2+z^2)^2 at z= 0
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Originally Posted by essedra Find the order of the pole f(z) = 1/(2cosz-2+z^2)^2 at z= 0 Lets analyze the denominator without the square
So now your fuction looks like
where the 2nd factor is non zero at zero.
Last edited by TheEmptySet; Jun 5th 2011 at 04:10 PM.
Why have you gone from
and why can't g(0) be 0. Thanks
Here is z=0 as pole of order 8
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