Show that sin(z+w) = sinz.cosw + cosz.sinw for all z, w that are complex numbers.
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Originally Posted by essedra Show that sin(z+w) = sinz.cosw + cosz.sinw for all z, w that are complex numbers. Surely you know that: $\displaystyle \sin(z)=\frac{1}{2i}\left(e^{iz}-e^{-iz}\right)$ &$\displaystyle ~\cos(w)=\frac{1}{2}\left(e^{iw}+e^{-iw}\right).$ Now go for it!
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